

Calculus: Area Under a Curve
Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Practice Problem
•
Hard
Standards-aligned
Mia Campbell
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the function whose area under the curve we are trying to determine?
f(x) = 9 + x^2
f(x) = 9x - x^3
f(x) = 9 - x^2
f(x) = x^2 - 9
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the interval [-3, 3] in this problem?
It is the interval over which we calculate the area.
It is where the function is undefined.
It is the interval where the function is negative.
It is the interval where the function is zero.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can we use symmetry to simplify the calculation of the area?
The function is even and symmetrical about the y-axis.
The function is odd.
The function is periodic.
The function is linear.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the antiderivative of the function 9 - x^2?
9x + x^3/3
9x - x^3/3
9x^2 + x^3/3
9x^2 - x^3
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in evaluating the definite integral from -3 to 3?
Substitute x = 0 into the function.
Find the derivative of the function.
Multiply the function by 2.
Find the antiderivative and evaluate it at the limits.
Tags
CCSS.HSA-REI.B.4B
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of substituting x = 3 into the antiderivative?
36
27 + 9
27 - 9
18
Tags
CCSS.6.G.A.1
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final calculated area of the shaded region?
27 square units
18 square units
36 square units
45 square units
Tags
CCSS.HSA-REI.B.4B
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