Differentiation and Tangent Line Concepts

Differentiation and Tangent Line Concepts

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to perform implicit differentiation on the equation involving square roots of x and y, and solve for dy/dx. It then demonstrates how to find the equation of the tangent line at a specific point using the derivative. The process includes converting square roots to rational exponents, applying the chain rule, and solving algebraically. Finally, the tutorial verifies the solution graphically.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial problem statement in the video?

Finding the maximum and minimum points

Solving for the roots of the equation

Determining dy/dx and the tangent line equation

Finding the value of x and y

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the square root of x expressed using rational exponents?

x^(1/2)

x^1

x^2

x^(1/3)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What rule is applied when differentiating a y term with respect to x?

Power rule

Product rule

Quotient rule

Chain rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of x^(1/2) with respect to x?

x^(-1/2)

1/2 * x^(1/2)

x^(1/2)

1/2 * x^(-1/2)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for dy/dx after solving the equation?

dy/dx = square root of x divided by square root of y

dy/dx = negative square root of y divided by square root of x

dy/dx = square root of y divided by square root of x

dy/dx = negative square root of x divided by square root of y

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the slope of the tangent line at the point (9, 16)?

-4/3

4/3

-3/4

3/4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the point-slope form of the tangent line equation?

y - 16 = -4/3(x - 9)

y - 16 = 4/3(x - 9)

y - 9 = -4/3(x - 16)

y - 9 = 4/3(x - 16)

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