Tangent Planes and Partial Derivatives

Tangent Planes and Partial Derivatives

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains the concept of tangent planes to surfaces, comparing it to tangent lines in two dimensions. It covers the derivation of the tangent plane equation using partial derivatives and provides a step-by-step example of calculating a tangent plane to a given surface. The tutorial concludes with a brief mention of further derivation in another video.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of a tangent line in 2D at a point (x1, f(x1))?

y - f(x1) = f'(x1) * (x - x1)

y = f(x1) + f'(x1) * (x - x1)

y + f(x1) = f'(x1) * (x + x1)

y = f(x1) - f'(x1) * (x - x1)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In 3D, what does the partial derivative of f with respect to x represent?

Slope of the tangent line in the positive x direction

Slope of the tangent line in the positive y direction

Slope of the tangent plane in the z direction

Slope of the tangent line in the negative x direction

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the z-coordinate of the point of tangency in the example problem?

3

4

5

6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the partial derivative of f with respect to x?

Differentiate f with respect to y, treating x as a constant

Differentiate f with respect to x, treating y as a constant

Differentiate f with respect to both x and y

Differentiate f with respect to x, treating z as a constant

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the partial derivative of f with respect to x at the point (-2, 1)?

0

-1

1

2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the partial derivative of f with respect to y at the point (-2, 1)?

0

-1

1

2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the tangent plane at the point (-2, 1, 5)?

z = x + 2y - 1

z = -x - 2y + 1

z = x - 2y + 1

z = -x + 2y + 1

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