Understanding Circle Area and Radius

Understanding Circle Area and Radius

Assessment

Interactive Video

Mathematics, Science

5th - 8th Grade

Hard

Created by

Sophia Harris

FREE Resource

The video tutorial explains how to determine the radius of a circle formed by a lawn sprinkler's spray, given its area as 625π square feet. It uses the formula for the area of a circle, A = πr², to find the radius. By substituting the given area into the formula and solving for r, the radius is found to be 25 feet. The tutorial also addresses whether a person standing 30 feet away from the sprinkler would get wet, concluding that they would not, as they are outside the circle's radius.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the area covered by the lawn sprinkler in terms of pi?

625 pi square feet

1250 square feet

625 square feet

1250 pi square feet

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the area of a circle?

A = 2 pi r

A = pi r

A = pi r squared

A = 2 pi r squared

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the radius from the area of a circle?

Divide both sides by pi

Subtract pi from both sides

Multiply both sides by pi

Add pi to both sides

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the radius of the circle if the area is 625 pi square feet?

15 feet

20 feet

25 feet

30 feet

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the principal square root of 625?

30

20

15

25

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the radius of a circle represent in this context?

The distance from the sprinkler to the edge of the area it covers

The distance from the sprinkler to the center of the circle

The distance from one side of the circle to the other

The distance from the edge of the circle to the ground

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical operation is used to find the radius from r-squared?

Addition

Multiplication

Subtraction

Square root

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