Trigonometric Identities and Simplifications

Trigonometric Identities and Simplifications

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Mia Campbell

FREE Resource

The video tutorial explains how to simplify a trigonometric expression to a single trig function using two methods. The first method involves simplifying the fraction and using trigonometric identities, while the second method uses a common denominator approach. Both methods ultimately simplify the expression to secant squared x. The tutorial emphasizes understanding and applying trigonometric identities effectively.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of the video tutorial?

To simplify a trigonometric expression to a single function

To calculate the area of a triangle

To learn how to solve quadratic equations

To understand the Pythagorean theorem

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first method, what is the first step to simplify the fraction?

Subtract the denominator from the numerator

Add the numerator and the denominator

Multiply the numerator by the denominator

Divide each term in the numerator by the denominator

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric identity is used to simplify two over cosine squared x?

Sine squared theta plus cosine squared theta equals one

One over cosine theta equals secant theta

Sine theta divided by cosine theta equals tangent theta

Tangent squared theta plus one equals secant squared theta

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of simplifying two secant squared x minus one secant squared x?

Sine squared x

Cosine squared x

Secant squared x

Tangent squared x

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second method, how is one rewritten to obtain a common denominator?

As sine squared x over sine squared x

As cosine squared x over cosine squared x

As tangent squared x over tangent squared x

As secant squared x over secant squared x

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common denominator used in the second method?

Secant squared x

Cosine squared x

Tangent squared x

Sine squared x

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which identity is used to simplify the numerator in the second method?

One over sine theta equals cosecant theta

Tangent squared theta plus one equals secant squared theta

Sine squared theta plus cosine squared theta equals one

Cosine theta divided by sine theta equals cotangent theta

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