Surface Area and Integration Concepts

Surface Area and Integration Concepts

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains how to find the surface area of revolution about the y-axis for the function y = cube root of 6x over the interval x = 0 to 4/3. It discusses the graph of the function, verifies values, and explores integration methods with respect to x and y. The tutorial solves for x, finds derivatives, and performs integration using u-substitution to calculate the surface area. Finally, it provides the exact and approximate surface area values.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function given for finding the surface area of revolution?

y = 6x cubed

y = square root of 6x

y = cube root of 6x

y = 6x squared

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the interval for x in the given problem?

[0, 3]

[0, 1]

[0, 4/3]

[0, 2]

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When rotating a curve about the y-axis, what are the two possible variables for integration?

x and z

y and z

x and y

z and w

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main factor in deciding whether to integrate with respect to x or y?

The length of the interval

The complexity of f'(x) or f'(y)

The value of the function at endpoints

The graph of the function

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for x in terms of y after solving the function y = cube root of 6x?

x = y^3 * 6

x = 6 / y^3

x = 6y^3

x = y^3 / 6

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative f'(y) of the function f(y) = y^3 / 6?

y^2 / 2

y^3 / 2

3y^2

1/2 y^2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used to evaluate the integral for the surface area?

u = y^3 / 6

u = y^2 / 2

u = 1 + y^4 / 4

u = y^4 / 4

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