Differential Equations and Integrals

Differential Equations and Integrals

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to solve an initial value problem using a separable differential equation. It begins by rewriting the given equation in a separable form, allowing for integration of both sides. U-substitution is used to simplify the integration process. The general solution is derived, and the initial condition is applied to find the particular solution. The tutorial emphasizes the importance of understanding the structure of separable differential equations and the steps involved in solving them.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition given in the problem?

y(0) = 1

y(1) = 0

y(1) = 11

y(0) = 11

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can separable differential equations be expressed?

As a quotient of functions of x and y

As a difference of functions of x and y

As a product of functions of x and y

As a sum of functions of x and y

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the greatest common factor used to factor the right side of the equation?

2x

y

2y

4x

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used for integration on the left side?

U = x^2

U = y^2

U = 2y - 1

U = 2x - 1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integral of 1/(2y - 1) with respect to y?

ln|2y - 1|

1/12 ln|2y - 1|

2 ln|2y - 1|

1/2 ln|2y - 1|

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the form of the general solution after solving for y?

y = C * e^(2x^2) + 1

y = C * e^(2x^2) - 1

y = C * e^(x^2) + 1

y = C * e^(x^2) - 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the constant C determined in the particular solution?

By setting x = 0 and y = 1

By setting x = 11 and y = 0

By setting x = 0 and y = 11

By setting x = 1 and y = 0

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