Understanding Linear Cost Equations

The video tutorial explains how to model a cell phone carrier's monthly cost using a linear equation. It provides a problem involving costs for different minutes used in January and February. The tutorial guides through calculating the slope, representing the cost per minute, and determining the fixed monthly fee. The final cost equation is derived, showing the relationship between minutes used and total cost.

What type of equation is used to model the cell phone carrier's charges?

• Logarithmic equation

• Linear equation

• Exponential equation

• Quadratic equation

Tags

CCSS.HSF.LE.B.5

In January, how much did the carrier charge for 250 minutes?

• $60

• $53

• $55

• $50

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CCSS.HSF.IF.A.2

What is the ordered pair for February's usage and cost?

• (250, 53)

• (150, 53)

• (250, 55)

• (150, 55)

Tags

CCSS.8.EE.B.5

How is the slope of the cost equation calculated?

• Sum of costs divided by sum of minutes

• Change in minutes divided by change in cost

• Change in cost divided by change in minutes

• Product of costs and minutes

Tags

CCSS.8.EE.B.5

What does the slope represent in the cost equation?

• Fixed monthly fee

• Total cost

• Constant rate per minute

• Number of minutes used

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

What is the form of the cost equation after finding the slope?

• c = b - 0.02x

• c = 0.02x - b

• c = bx + 0.02

• c = 0.02x + b

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CCSS.8.EE.C.8C

Which ordered pair is used to solve for the fixed fee?

• (150, 53)

• (100, 52)

• (250, 55)

• (200, 54)

What is the fixed monthly fee charged by the carrier?

• $50

• $55

• $52

• $53

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

What is the complete cost equation derived in the video?

• c = 0.02x + 50

• c = 0.02x + 53

• c = 0.02x + 55

• c = 0.02x + 52

Tags

CCSS.HSF.LE.B.5

If no minutes are used, what is the cost according to the equation?

• $0

• $50

• $53

• $55

Tags

CCSS.HSF.LE.B.5