Solving Separable Differential Equations

Solving Separable Differential Equations

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to solve a separable differential equation using an initial condition. It begins by rearranging the equation to separate variables, then integrates both sides. The solution is further refined by solving for y and applying the initial condition to find the particular solution. The process involves factoring, integration, and substitution techniques.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a separable differential equation?

Integrate both sides immediately

Factor the numerator

Rearrange the equation to separate variables

Apply the initial condition

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general form of a separable differential equation?

A function of y equals a function of t

A function of y times dy equals a function of t times dt

A function of t equals a function of y

A function of y plus a function of t equals zero

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we multiply both sides of the equation by y in the factoring step?

To apply the initial condition

To simplify the equation

To move y to the numerator

To eliminate y from the equation

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What technique is used to integrate the right side of the equation?

Partial fraction decomposition

Integration by parts

U-substitution

Trigonometric substitution

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of integrating y dy?

ln(y) + C

2y + C

y^2/2 + C

y^2 + C

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of taking the square root when solving for y?

To find the particular solution

To solve for the constant of integration

To ensure y is positive

To simplify the equation

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the absolute value not needed in the final solution?

Because it simplifies the equation

Because the initial condition is applied

Because y is always positive

Because t^2 + 1 is always positive

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