Solving Separable Differential Equations

The video tutorial explains how to solve a separable differential equation using an initial condition. It begins by rearranging the equation to separate variables, then integrates both sides. The solution is further refined by solving for y and applying the initial condition to find the particular solution. The process involves factoring, integration, and substitution techniques.

What is the first step in solving a separable differential equation?

• Integrate both sides immediately

• Factor the numerator

• Rearrange the equation to separate variables

• Apply the initial condition

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CCSS.HSA.REI.A.1

What is the general form of a separable differential equation?

• A function of y equals a function of t

• A function of y times dy equals a function of t times dt

• A function of t equals a function of y

• A function of y plus a function of t equals zero

Tags

CCSS.HSA.REI.A.1

Why do we multiply both sides of the equation by y in the factoring step?

• To apply the initial condition

• To simplify the equation

• To move y to the numerator

• To eliminate y from the equation

What technique is used to integrate the right side of the equation?

• Partial fraction decomposition

• Integration by parts

• U-substitution

• Trigonometric substitution

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CCSS.HSA.REI.A.2

What is the result of integrating y dy?

• ln(y) + C

• 2y + C

• y^2/2 + C

• y^2 + C

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CCSS.HSA-REI.B.4B

What is the purpose of taking the square root when solving for y?

• To find the particular solution

• To solve for the constant of integration

• To ensure y is positive

• To simplify the equation

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CCSS.HSA.REI.A.2

Why is the absolute value not needed in the final solution?

• Because it simplifies the equation

• Because the initial condition is applied

• Because y is always positive

• Because t^2 + 1 is always positive

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CCSS.HSA.REI.A.2

How is the constant of integration determined?

• By integrating again

• By using the initial condition

• By differentiating the equation

• By setting it to zero

What is the particular solution given the initial condition y(0) = 3?

• y = sqrt(ln(t^2 + 1) + 9)

• y = ln(t^2 + 1) + C

• y = sqrt(t^2 + 1) + 9

• y = ln(t^2 + 1) + 3

What is the role of the initial condition in solving the differential equation?

• To eliminate variables

• To simplify the integration process

• To find the constant of integration

• To determine the form of the equation