Differential Equations and Initial Conditions

Differential Equations and Initial Conditions

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to verify if a given function is a solution to a differential equation for any value of c and how to find a specific value of c that satisfies an initial condition. It covers the process of finding derivatives, substituting into the equation, and simplifying terms to verify the solution. The tutorial also demonstrates solving for c using the initial condition and provides a decimal approximation for the value of c.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main goal of part a in the problem statement?

To determine the initial condition

To solve the equation for y

To verify the function as a solution

To find the value of c

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for y in terms of c and x?

c e^x + e^x

c e^(-2x) + e^(-x)

c e^(2x) + e^x

c e^(-x) + e^(-2x)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of e^(-x) with respect to x?

e^(-x)

-e^(-x)

e^(x)

-e^(x)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After substituting y and y' into the differential equation, what is the next step?

Differentiate again

Integrate both sides

Combine like terms

Solve for x

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the simplification of the differential equation verify?

The function is not a solution

The function is a solution for c=1

The function is a solution for any c

The function is a solution for c=0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What initial condition is used to find the particular solution?

y(0) = 0

y(1) = 1

y(-4) = 4

y(4) = -4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the value of c using the initial condition?

By integrating the equation

By substituting x = -4 and y = 4

By setting x = 0

By differentiating the equation

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