

Partial Derivatives and Tangent Lines
Interactive Video
•
Mathematics
•
10th - 12th Grade
•
Practice Problem
•
Hard
Olivia Brooks
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the function f(x, y) given in the problem?
f(x, y) = 3x^2 + 5y^2
f(x, y) = sqrt(3x^2 + 5y^2)
f(x, y) = 3x + 5y
f(x, y) = (3x^2 + 5y^2)^2
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the partial derivative of f with respect to x represent at the point (1, 3)?
The slope of the tangent line in the y direction
The slope of the tangent line in the x direction
The curvature of the surface
The maximum value of the function
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why do we expect the partial derivative with respect to x to be positive?
Because the tangent line is going uphill
Because the function is constant
Because the tangent line is going downhill
Because the function is decreasing
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the function f(x, y) rewritten using rational exponents?
f(x, y) = (3x^2 + 5y^2)^0.5
f(x, y) = (3x^2 + 5y^2)^2
f(x, y) = (3x^2 + 5y^2)^-1
f(x, y) = (3x^2 + 5y^2)^1
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the inner function u when applying the chain rule?
u = 3x^2 + 5y^2
u = 3x^2 - 5y^2
u = 3x + 5y
u = x^2 + y^2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the derivative of u with respect to x?
6x
0
5y
3x
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the expression simplified after applying the chain rule?
3x / (3x^2 + 5y^2)^0.5
3x * (3x^2 + 5y^2)^-0.5
3x * (3x^2 + 5y^2)^0.5
3x / (3x^2 + 5y^2)^2
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