Population Dynamics and Linear Equations

Population Dynamics and Linear Equations

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

CCSS
6.EE.B.7, 7.EE.B.4A, HSF-LE.A.1C

+7

Standards-aligned

Created by

Amelia Wright

FREE Resource

Standards-aligned

CCSS.6.EE.B.7
,
CCSS.7.EE.B.4A
,
CCSS.HSF-LE.A.1C
CCSS.HSF.LE.A.2
,
CCSS.HSF-BF.A.1A
,
CCSS.8.F.B.4
,
CCSS.7.NS.A.2A
,
CCSS.HSF.LE.A.4
,
CCSS.HSF.IF.B.6
,
CCSS.7.NS.A.2B
,
The video tutorial explains how to solve a linear equation to determine the number of years it will take for a town's population to decrease from 280,000 to 269,800 due to a yearly decrease of 850 people. It involves defining variables, formulating the equation, and solving for the time variable. The solution shows that it will take 12 years for the population to reach the target number.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial population of the town mentioned in the problem?

269,800

850

280,000

300,000

Tags

CCSS.HSF-LE.A.1C

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

By how much does the population decrease each year?

500

1,000

750

850

Tags

CCSS.HSF.LE.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the variable 'P' represent in the equation?

Population of the town

Time in years

Initial population

Rate of change

Tags

CCSS.HSF-BF.A.1A

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation used to represent the population after T years?

P = 280,000 - 850T

P = 280,000 + 850T

P = 269,800 + 850T

P = 269,800 - 850T

Tags

CCSS.8.F.B.4

CCSS.HSF.IF.B.6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the rate of change in the population?

Constant

Zero

Positive

Negative

Tags

CCSS.6.EE.B.7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What value is substituted for P to solve the equation?

280,000

269,800

850

12

Tags

CCSS.6.EE.B.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in isolating the variable T?

Multiply both sides by 850

Subtract 280,000 from both sides

Add 850 to both sides

Divide both sides by 280,000

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

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