Understanding Perpendicular Bisectors in Triangles

Understanding Perpendicular Bisectors in Triangles

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

This video tutorial explains how to solve for unknown values using the properties of perpendicular bisectors in triangles. It covers two examples: one for finding x and another for finding y, using congruence and perpendicularity properties. A special case is also discussed where the bisector passes through the opposite vertex, demonstrating the equal distance property of points on the bisector.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What property of a perpendicular bisector is used to determine the angle it forms with the side of a triangle?

It is parallel to the side.

It forms a 45-degree angle.

It is perpendicular, forming a 90-degree angle.

It bisects the angle at the vertex.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what equation is set up to solve for x?

x - 6 = 90

2x = 90

2x + 6 = 90

x + 6 = 90

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the length of the segment determined in the first example?

By adding the lengths of two segments.

By doubling the given length.

By subtracting from the total length.

By dividing the total length by two.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of y in the first example?

10

9

8

7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation is used to solve for y in the first example?

y + 1 = 23

3y - 1 = 23

3y + 1 = 23

y - 1 = 23

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the second example, what makes the problem a special case?

The bisector is parallel to the base.

The bisector is shorter than the side.

The bisector passes through the opposite vertex.

The bisector is longer than the side.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What property of the perpendicular bisector is highlighted in the second example?

It is equidistant from the endpoints of the segment.

It is always parallel to the base.

It forms a 45-degree angle with the base.

It divides the triangle into two equal areas.

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