Understanding Tape Diagrams in Running Distances

The video tutorial explains how to determine the distance Keisha could run in one minute three years ago, given that she can currently run 170 meters in one minute, which is 125% of her past distance. The instructor uses fractions to convert percentages and employs a tape diagram to visualize the problem. By dividing 170 meters by 5, the instructor calculates that each fourth is 34 meters, leading to the conclusion that Keisha could run 136 meters in one minute three years ago.

What is the current distance Keisha can run in one minute?

• 200 meters

• 150 meters

• 170 meters

• 125 meters

What percentage of her past running distance does Keisha's current distance represent?

• 125%

• 175%

• 150%

• 100%

How can 125% be expressed as a fraction?

• 3/2

• 6/5

• 5/4

• 4/5

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CCSS.3.NF.A.1

CCSS.3.NF.A.2B

What does the tape diagram help us visualize?

• The total distance Keisha can run today

• The difference between Keisha's past and current distances

• The time it takes Keisha to run 170 meters

• The fraction of the distance she could run three years ago

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CCSS.5.NF.B.7A

CCSS.5.NF.B.7C

How many equal sections are drawn in the tape diagram?

• 6

• 3

• 5

• 4

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CCSS.4.MD.A.2

What is the length of each section in the tape diagram?

• 34 meters

• 40 meters

• 30 meters

• 36 meters

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CCSS.3.OA.D.8

How do you calculate the past running distance from the tape diagram?

• Divide the total distance by 5

• Multiply the total distance by 5

• Add the lengths of all sections

• Multiply one section by 4

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CCSS.3.OA.B.6

What operation is used to find the size of each section in the tape diagram?

• Division

• Subtraction

• Multiplication

• Addition

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CCSS.4.MD.A.1

What is the past running distance Keisha could achieve in one minute?

• 136 meters

• 140 meters

• 130 meters

• 134 meters

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CCSS.7.EE.B.3

What is the final step to find the past running distance?

• Add the current distance to the past distance

• Multiply the size of one section by 4

• Divide the current distance by 4

• Subtract the current distance from the past distance

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CCSS.7.EE.B.3