Search Header Logo
Understanding Enthalpy of Formation

Understanding Enthalpy of Formation

Assessment

Interactive Video

Chemistry, Science

10th - 12th Grade

Practice Problem

Easy

Created by

Olivia Brooks

Used 2+ times

FREE Resource

The video tutorial explains the concept of enthalpy of formation, focusing on the formation of substances like carbon dioxide, water, and methane from their most stable elements under standard conditions. It discusses the standard enthalpy of formation for elements and how to calculate the enthalpy change for chemical reactions using the enthalpies of formation of products and reactants. The tutorial also covers the significance of standard conditions and the zero enthalpy of formation for the most stable form of elements.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the superscript naught (°) indicate in the context of enthalpy of formation?

The reaction involves a catalyst.

The reaction is exothermic.

The reaction occurs at standard state conditions.

The reaction occurs at high pressure.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which form of carbon is used when calculating the standard enthalpy of formation for carbon dioxide?

Diamond

Graphite

Fullerene

Amorphous carbon

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the standard enthalpy of formation for one mole of water?

-393.5 kJ/mol

-285.8 kJ/mol

0 kJ/mol

-74.8 kJ/mol

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the standard enthalpy of formation for diatomic oxygen gas (O2) zero?

It is a highly reactive form.

It is the most stable form of oxygen under standard conditions.

It is an unstable form of oxygen.

It is a rare form of oxygen.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following has a non-zero standard enthalpy of formation?

Graphite

Hydrogen gas (H2)

Diatomic oxygen gas (O2)

Ozone (O3)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is true about the standard enthalpy of formation for diamond?

It is zero because diamond is a common form of carbon.

It is zero because diamond is the most stable form of carbon.

It is greater than zero because diamond is not the most stable form of carbon.

It is less than zero because diamond is highly reactive.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the standard enthalpy change for the combustion of one mole of methane?

-285.8 kJ

-393.5 kJ

-74.8 kJ

-890.3 kJ

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?