The video tutorial explains how to divide a polynomial expression by a monomial using two different methods. The first method involves rewriting the expression and applying the distributive property, while the second method focuses on factoring the numerator to simplify the division. Both approaches lead to the same result, demonstrating the flexibility in solving polynomial division problems.

What is the initial expression that needs to be divided by x?

• x to the fourth minus 2x squared plus 5

• x to the fourth plus 2x to the third minus 5x

• x to the fourth minus 2x to the third plus 5x

• x to the third minus 2x squared plus 5

Tags

CCSS.HSA.APR.A.1

In the first method, what is the expression rewritten as before distributing 1/x?

• x to the third minus 2x squared plus 5

• x to the fourth minus 2x to the third plus 5x

• 1 over x times (x to the fourth minus 2x to the third plus 5x)

• x times (x to the third minus 2x squared plus 5)

Tags

CCSS.HSA.APR.A.1

What is the result of simplifying x to the fourth divided by x?

• x to the fourth

• x to the third

• x to the first

• x to the second

What is the simplified form of -2x to the third divided by x?

• -2x to the third

• -2x

• -2

• -2x squared

What is the final term when 5x is divided by x?

• 0

• x

• 5

• 5x

Tags

CCSS.HSF-IF.C.7C

What is the purpose of multiplying the simplified expression by x in the verification step?

• To check if the original expression is obtained

• To find the derivative

• To simplify further

• To factor out x

In the second method, what is factored out from the numerator?

• x squared

• 5

• 2x

• x

What is the expression after factoring out x in the second method?

• x times (x to the third minus 2x squared plus 5)

• x to the third minus 2x squared plus 5

• x to the fourth minus 2x to the third plus 5x

• x times (x to the fourth minus 2x to the third plus 5x)

Tags

CCSS.HSA.APR.D.6

What happens to the x in the numerator and denominator after factoring?

• They remain unchanged

• They cancel out

• They multiply

• They add up

Tags

CCSS.HSA.APR.D.6

What is the key concept behind both methods discussed?

• Multiplying by x

• Factoring out common terms

• Using exponent properties

• Dividing by zero

Tags

CCSS.HSA.APR.D.6