Multiplication Using the Standard Algorithm

This video tutorial demonstrates how to multiply 6742 by 23 using the standard algorithm. It begins with an introduction to the problem and encourages viewers to attempt solving it independently. The video then explains the standard algorithm, breaking down the multiplication process into steps: multiplying by ones and tens, and finally adding the results to obtain the final answer. The tutorial emphasizes understanding the underlying concepts and the importance of place value in multiplication.

What is the main focus of this video tutorial?

• Studying subtraction methods

• Learning to divide large numbers

• Exploring addition techniques

• Understanding the standard algorithm for multiplication

Tags

CCSS.5.NBT.B.5

How are the numbers 6742 and 23 aligned for multiplication?

• By aligning the hundreds place

• By aligning the units place

• By aligning the place values

• By aligning the decimal points

Tags

CCSS.4.NBT.B.5

What is the first step in multiplying 6742 by 3?

• Multiply 4 by 3

• Multiply 6 by 3

• Multiply 2 by 3

• Multiply 7 by 3

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CCSS.5.NBT.A.2

What happens when you multiply 4 tens by 3?

• You get 12 tens, which is written as 2 tens and 1 hundred

• You get 12 tens, which is written as 0 tens and 1 hundred

• You get 12 tens, which is written as 1 ten and 2 hundreds

• You get 12 tens, which is written as 3 tens and 0 hundreds

Tags

CCSS.4.NBT.B.5

Why is a zero added when multiplying by 20?

• To make the calculation easier

• To decrease the result

• To avoid mistakes in place value

• To increase the result

Tags

CCSS.3.NBT.A.3

What is the result of multiplying 4 tens by 2 tens?

• 800

• 40

• 80

• 8

Tags

CCSS.4.NBT.B.5

What is the next step after multiplying by 20?

• Adding the partial products

• Dividing the partial products

• Multiplying the partial products

• Subtracting the partial products

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CCSS.2.NBT.B.7

What is the sum of two hundreds and eight hundreds?

• Twenty hundreds

• Eighteen hundreds

• Ten hundreds

• Six hundreds

Tags

CCSS.5.NBT.B.5

What is the final result of multiplying 6742 by 23?

• 150,060

• 150,506

• 155,006

• 155,060

Tags

CCSS.4.NF.B.4C

CCSS.4.NF.B.4B

What is the importance of understanding different multiplication methods?

• To make calculations slower

• To understand the underlying concepts

• To confuse students

• To avoid using calculators

Tags

CCSS.4.NF.B.4C

CCSS.4.NF.B.4B