Potato Temperature Change Analysis

Potato Temperature Change Analysis

Assessment

Interactive Video

Mathematics, Science

11th Grade - University

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial covers the 2017 AP Calculus exam's potato cooling problem. It explains how the internal temperature of a potato, initially at 91°C, cools over time in a room with an ambient temperature of 27°C. The cooling process is modeled by a differential equation. The tutorial derives the equation for the tangent line at T=0 and uses it to approximate the potato's temperature at T=3.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial internal temperature of the potato at time T equals zero?

27 degrees Celsius

50 degrees Celsius

91 degrees Celsius

100 degrees Celsius

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the ambient room temperature assumed to be in the problem?

30 degrees Celsius

25 degrees Celsius

27 degrees Celsius

20 degrees Celsius

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the differential equation describe in the context of the potato problem?

The rate of heating of the potato

The constant temperature of the potato

The increase in ambient temperature

The rate of cooling of the potato

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the rate of change of temperature relate to the difference between the potato's temperature and the ambient temperature?

It is directly proportional

It is unrelated

It is constant

It is inversely proportional

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What shape does the graph of the potato's temperature over time resemble?

A straight line

A parabola

An exponential decay curve

A sine wave

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the rate of change as the potato's temperature approaches the ambient temperature?

It remains constant

It becomes more positive

It becomes less negative

It becomes zero

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation of the tangent line to the graph of H at T equals 0?

Y = -16T + 91

Y = 1/4T + 27

Y = 16T + 91

Y = -1/4T + 27

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?