Maclaurin Series and Function Analysis

Maclaurin Series and Function Analysis

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

CCSS
HSA.APR.C.5, HSF.BF.A.2

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.HSA.APR.C.5
,
CCSS.HSF.BF.A.2
The video tutorial explains how to find the Maclaurin series representation of a function, specifically f(x) = x^3 * cos(x^2). It highlights the challenges of calculating derivatives and offers a simpler approach by using the known Maclaurin series for cosine. The tutorial guides viewers through substituting x with x^2 in the cosine series and multiplying by x^3 to find the first five non-zero terms of the series. The video concludes with a strategy for using known series to simplify complex calculations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main challenge in finding the Maclaurin series for the given function?

Finding the function's roots

Calculating the derivatives

Identifying the function's asymptotes

Determining the function's domain

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the Maclaurin series centered at?

Infinity

One

Zero

Negative one

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which function's Maclaurin series is used as a hint in the video?

Exponential

Sine

Cosine

Logarithm

Tags

CCSS.HSF.BF.A.2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is made in the cosine series to help find the series for the given function?

Replace x with x^2

Replace x with x^3

Replace x with 2x

Replace x with 1/x

Tags

CCSS.HSA.APR.C.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first non-zero term in the series for the given function?

x^3

x^5

x^7

x^9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many non-zero terms are calculated in the series for the given function?

Three

Six

Four

Five

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the benefit of using the known Maclaurin series for cosine in this problem?

It avoids complex integration

It simplifies the derivative calculations

It provides a direct solution

It eliminates the need for limits

Tags

CCSS.HSA.APR.C.5

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