Why can't person A and person B push the box directly towards the target?

Force Vectors and Trigonometric Components

Interactive Video
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Physics, Mathematics
•
9th - 12th Grade
•
Hard

Aiden Montgomery
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
There is no good footing behind the box.
They are not strong enough.
The box is too heavy.
The box is too slippery.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the magnitude of the force vector exerted by person A?
320 newtons
300 newtons
330 newtons
350 newtons
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
At what angle is person B pushing relative to the target direction?
25 degrees
15 degrees
20 degrees
10 degrees
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which trigonometric function is used to find the component of the force in the target direction?
Cosine
Tangent
Sine
Secant
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you calculate the component of person A's force in the target direction?
330 times sine of 35 degrees
300 times sine of 35 degrees
330 times cosine of 35 degrees
300 times cosine of 35 degrees
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the component of person B's force in the target direction?
270 newtons
300 newtons
280 newtons
290 newtons
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Who contributes more force in the direction of the target?
Both contribute equally
Person B
Person A
Neither contributes
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