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Critical Points and Area Minimization

Critical Points and Area Minimization

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Practice Problem

Hard

CCSS
8.EE.A.2

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.8.EE.A.2
The video tutorial explains how to optimize the combined area of an equilateral triangle and a square by finding the critical points of a function. It involves taking the derivative, solving for x, and using the second derivative test to confirm a minimum point. The optimal cut is determined to minimize the area, with calculations verified using a calculator.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the problem discussed in the video?

To find the minimum combined area of a triangle and a square

To calculate the perimeter of a square

To determine the volume of a cube

To find the maximum area of a triangle

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the critical points of the function?

Using a calculator

Taking the derivative of the function

Graphing the function

Calculating the area

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical operation is used to find where the derivative is zero?

Division

Addition

Multiplication

Subtraction

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What tool is used to calculate the critical point value of x?

A calculator

A compass

A protractor

A ruler

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of x that minimizes the area?

25.5

12.5

50.2

39.38

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What test is used to determine if the critical point is a minimum or maximum?

First derivative test

Second derivative test

Third derivative test

Fourth derivative test

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a positive second derivative indicate about the function?

The function is constant

The function is concave downwards

The function is concave upwards

The function is linear

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