Understanding Definite Integrals and Temperature Changes

Understanding Definite Integrals and Temperature Changes

Assessment

Interactive Video

Mathematics, Science

9th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial covers evaluating definite integrals using the second fundamental theorem of calculus. It explains how to calculate the change in temperature over a period by evaluating the integral of a derivative function. The tutorial also applies this concept to a real-world problem involving the cooling of biscuits and tea, demonstrating how to determine the temperature difference between two objects after a given time.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main purpose of evaluating the definite integral from 0 to 10 of H prime of (t)dt in this context?

To find the average temperature over 10 minutes

To determine the change in temperature over 10 minutes

To measure the rate of temperature change

To calculate the initial temperature

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which theorem is used to evaluate the definite integral in this problem?

First Fundamental Theorem of Calculus

Mean Value Theorem

Second Fundamental Theorem of Calculus

Intermediate Value Theorem

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the temperature change for the tea from 0 to 10 minutes?

43 degrees Celsius increase

23 degrees Celsius increase

43 degrees Celsius decrease

23 degrees Celsius decrease

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At what temperature were the biscuits initially removed from the oven?

34 degrees Celsius

100 degrees Celsius

43 degrees Celsius

66 degrees Celsius

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function B used for in the context of the biscuits?

To model the temperature of the biscuits over time

To calculate the initial temperature

To determine the final temperature

To model the rate of temperature increase

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the change in temperature for the biscuits over 10 minutes?

65.82 degrees Celsius increase

65.82 degrees Celsius decrease

23 degrees Celsius decrease

43 degrees Celsius increase

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much cooler are the biscuits than the tea after 10 minutes?

23 degrees Celsius warmer

23 degrees Celsius cooler

8.82 degrees Celsius warmer

8.82 degrees Celsius cooler

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