Fibonacci Sequence and Golden Ratio

Fibonacci Sequence and Golden Ratio

Assessment

Interactive Video

Mathematics

7th - 12th Grade

Hard

Created by

Emma Peterson

FREE Resource

This video tutorial explores the Fibonacci sequence and the golden ratio. It begins with an introduction to the Fibonacci sequence, explaining how each term is the sum of the two preceding ones. The video then delves into the golden ratio, illustrating how it is derived from the ratios of successive Fibonacci terms. Methods for calculating Fibonacci terms using the golden ratio are discussed, along with a detailed derivation of the golden ratio itself. The tutorial concludes with practical examples and mathematical explanations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first term in the Fibonacci sequence?

3

2

0

1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is each term in the Fibonacci sequence generated?

By multiplying the previous two terms

By subtracting the previous term from the next

By adding the previous two terms

By dividing the previous term by the next

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of the golden ratio?

1.5

1.618

1.414

2.0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which mathematical operation is used to derive the golden ratio from the Fibonacci sequence?

Multiplication

Subtraction

Addition

Division

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can the golden ratio be used in the Fibonacci sequence?

To determine the first term

To calculate the difference between terms

To find the sum of all terms

To approximate the next term

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the Fibonacci sequence as n becomes very large?

It becomes a constant sequence

It remains unchanged

It approximates a geometric sequence

It becomes a decreasing sequence

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate Fibonacci numbers using the golden ratio?

f(n) = (1 + sqrt(5))^n / 2^n

f(n) = n^2 + 1

f(n) = n + sqrt(5)

f(n) = (1 - sqrt(5))^n / 2^n

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