Understanding Kinetic Energy of Gas Molecules

Understanding Kinetic Energy of Gas Molecules

Assessment

Interactive Video

Physics, Chemistry, Science

10th - 12th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to calculate the average translational kinetic energy of gas molecules using two different approaches: one for individual molecules and another for moles of gas. It covers the necessary formulas, including the use of Boltzmann's constant and the ideal gas law, and demonstrates how to derive one equation from the other. The tutorial emphasizes the importance of understanding units and provides examples to illustrate the calculations.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to calculate the average translational kinetic energy of gas molecules?

2/3 RT

3/2 RT

2/3 KT

3/2 KT

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of Boltzmann's constant used in the kinetic energy calculation?

8.314 J/mol K

1.38 * 10^-21 J/K per molecule

1.38 * 10^-23 J/K per molecule

6.02 * 10^23 molecules/mol

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the average kinetic energy of 50 gas molecules at 400 Kelvin?

3 * 1.38 * 10^-21 * 400 / 2

3 * 8.314 * 400 / 2

3 * 1.38 * 10^-23 * 400 / 2

3 * 6.02 * 10^23 * 400 / 2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for calculating the average kinetic energy of moles of gas molecules?

2/3 nRT

2/3 KT

3/2 KT

3/2 nRT

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of the gas constant R used in the kinetic energy calculation for moles?

8.3145 J/K per molecule

6.02 * 10^23 molecules/mol

1.38 * 10^-23 J/K per molecule

8.3145 J/mol K

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the number of moles related to the number of molecules in the kinetic energy formula?

n = N/Na

n = Na/N

n = Na * N

n = N * Na

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is Avogadro's number used in the derivation of the kinetic energy formula?

6.02 * 10^23 molecules/mol

1.38 * 10^-23 J/K per molecule

8.3145 J/mol K

6.02 * 10^-21 molecules/mol

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