Electric Flux and Gauss's Law

Electric Flux and Gauss's Law

Assessment

Interactive Video

Physics, Science

10th - 12th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains the concept of a spherical conductor with a surface charge density and how to calculate the total charge on the sphere. It then covers the calculation of electric flux using Gauss's Law and derives the electric field at a distance from the sphere. An alternative method for deriving the electric field is also presented. The video concludes with additional resources for further learning.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula to calculate the total charge on a spherical conductor?

Charge density multiplied by the surface area of the sphere

Charge density multiplied by the volume of the sphere

Charge density divided by the surface area of the sphere

Charge density divided by the radius of the sphere

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which law is used to calculate the electric flux through a Gaussian surface?

Faraday's Law

Gauss's Law

Coulomb's Law

Ohm's Law

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between electric flux and the total charge enclosed?

Electric flux is the total charge divided by permittivity

Electric flux is the sum of total charge and permittivity

Electric flux is the product of total charge and permittivity

Electric flux is the total charge multiplied by permittivity

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the permittivity of free space in Gauss's Law?

It is used to calculate the total charge

It determines the strength of the electric field

It is a constant that relates electric flux to charge

It is used to calculate the surface area

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the electric field at the edge of a Gaussian surface calculated?

By multiplying the charge density times the radius of the conductor by permittivity and the radius of the Gaussian surface

By dividing the charge density times the radius of the conductor by permittivity and the radius of the Gaussian surface

By dividing the charge density by the radius of the Gaussian surface

By multiplying the charge density with the radius of the Gaussian surface

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the electric field at a point outside a spherical conductor?

It is inversely proportional to the distance from the center

It is zero

It is the same as inside the conductor

It behaves as if the conductor is a point charge

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Under what condition can a spherical conductor be treated as a point charge?

When the radius of the Gaussian surface is zero

When the radius of the Gaussian surface is greater than the radius of the conductor

When the radius of the Gaussian surface is less than the radius of the conductor

When the radius of the Gaussian surface is equal to the radius of the conductor

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