Understanding Derivatives and Integrals

Understanding Derivatives and Integrals

Assessment

Interactive Video

Mathematics

10th - 12th Grade

Hard

CCSS
HSF-IF.C.7E, HSF-BF.A.1B, HSF-IF.C.7D

Standards-aligned

Created by

Lucas Foster

FREE Resource

Standards-aligned

CCSS.HSF-IF.C.7E
,
CCSS.HSF-BF.A.1B
,
CCSS.HSF-IF.C.7D
The video tutorial explains how to find the rate of change of the vertical distance H between two functions, F and G, with respect to X. It demonstrates using a calculator to evaluate derivatives and integrals, emphasizing the importance of understanding the underlying concepts. The tutorial guides viewers through inputting functions into a calculator and evaluating derivatives at a specific point, highlighting the practical use of technology in solving calculus problems.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the problem discussed in the video?

To find the intersection points of f and g.

To determine the rate of change of H with respect to x.

To find the maximum value of H.

To calculate the integral of H over a region.

Tags

CCSS.HSF-BF.A.1B

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the function H(x) defined in terms of f(x) and g(x)?

H(x) = f(x) - g(x)

H(x) = f(x) * g(x)

H(x) = f(x) + g(x)

H(x) = g(x) - f(x)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What tool is suggested for evaluating derivatives and integrals during an AP test?

A scientific calculator

A graphing calculator

A computer algebra system

A slide rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for f(x) as defined in the video?

f(x) = 1 + x + e^(x^2) - 2x

f(x) = x^2 + 2x + 1

f(x) = e^x + x^2 - 1

f(x) = x^3 - 3x + 2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the expression for g(x) as defined in the video?

g(x) = x^4

g(x) = x^3

g(x) = x^2

g(x) = x

Tags

CCSS.HSF-IF.C.7D

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of the absolute value in the function H(x) as discussed?

To ensure H(x) is always positive.

To ensure H(x) is always negative.

To simplify the calculation of derivatives.

To make H(x) equal to zero.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of the derivative of H at x = 1.8?

2.812

-3.812

3.812

-2.812

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