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Circuit Analysis and Current Flow

Circuit Analysis and Current Flow

Assessment

Interactive Video

Physics, Science

10th - 12th Grade

Practice Problem

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to solve a circuit using the node voltage method. It begins with an introduction to the circuit components, including a voltage source, resistors, and a current source. The tutorial then identifies nodes and applies Kirchhoff's current law to establish equations for current flow. Using Ohm's law, the video demonstrates how to calculate the current through each resistor and determine the electric potential at various points in the circuit. The tutorial concludes with a second example, reinforcing the concepts and methods discussed.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial voltage of the source in the circuit described in the video?

60 volts

50 volts

70 volts

80 volts

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to Kirchhoff's Current Law, what should the sum of currents at a junction equal?

Zero

The voltage at the junction

The resistance at the junction

The power at the junction

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the current through a resistor calculated using Ohm's Law?

Current divided by resistance

Voltage times resistance

Voltage divided by resistance

Current times resistance

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the electric potential at point A after solving the circuit?

30 volts

40 volts

50 volts

60 volts

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the new circuit example, what is the value of the independent current source?

8 amps

5 amps

7 amps

6 amps

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the resistance of R4 in the new circuit example?

3 ohms

4 ohms

5 ohms

6 ohms

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the direction of current flow between two nodes?

By measuring the current directly

By comparing the electric potentials

By comparing the resistances

By guessing

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