Understanding Circle and Hyperbola Intersections

Understanding Circle and Hyperbola Intersections

Assessment

Interactive Video

Mathematics

9th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explores the intersection of a circle and a hyperbola, focusing on finding a common tangent with a positive slope. It begins by completing the square for the circle's equation, then analyzes the hyperbola's properties. The tutorial concludes by visualizing and determining the common tangent line, emphasizing the geometric relationships and constraints involved.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the problem involving the circle and the hyperbola?

To determine the area of the circle.

To find the intersection points of the circle and hyperbola.

To find a common tangent with a positive slope.

To calculate the volume of the hyperbola.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the center of the circle after completing the square?

(0, 4)

(8, 0)

(4, 0)

(0, 0)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the radius of the circle?

5

3

4

2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does the hyperbola open based on its equation?

In a circular manner

Up and down

Left and right

Diagonally

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the x-intercepts of the hyperbola?

(0, 0)

(4, 0) and (-4, 0)

(3, 0) and (-3, 0)

(5, 0) and (-5, 0)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a key requirement for the common tangent to the circle and hyperbola?

It must have a negative slope.

It must pass through the origin.

It must have a positive slope.

It must be horizontal.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't the common tangent be tangent to the circle where it has a negative slope?

Because it would be parallel to the x-axis.

Because it would not intersect the hyperbola.

Because it would be tangent to the y-axis.

Because it would have a positive slope.

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