Understanding the Distributive Law

Understanding the Distributive Law

Assessment

Interactive Video

Mathematics

5th - 8th Grade

Practice Problem

Easy

CCSS
3.OA.B.5, 3.OA.C.7, 1.OA.A.1

+4

Standards-aligned

Created by

Liam Anderson

Used 1+ times

FREE Resource

Standards-aligned

CCSS.3.OA.B.5
,
CCSS.3.OA.C.7
,
CCSS.1.OA.A.1
CCSS.3.NBT.A.3
,
CCSS.2.OA.C.4
,
CCSS.4.NBT.B.6
,
CCSS.5.NBT.B.6
,
The video tutorial explains how to rewrite and simplify expressions using the distributive law of multiplication over addition. It begins by evaluating expressions with parentheses and then demonstrates the distributive law by distributing the multiplier across terms inside the parentheses. A visual representation is provided to help understand why the distributive property works, showing how multiplication distributes over addition by duplicating terms.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial expression discussed in the video?

4 times (3 plus 8)

3 times (4 plus 8)

8 times (4 plus 3)

4 times (8 plus 3)

Tags

CCSS.1.OA.A.1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of evaluating 8 plus 3?

10

11

13

12

Tags

CCSS.3.NBT.A.3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 4 times 11?

42

48

44

40

Tags

CCSS.3.OA.B.5

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the distributive law allow you to do?

Multiply each term inside the parentheses separately

Divide each term inside the parentheses separately

Subtract numbers before multiplying

Add numbers before multiplying

Tags

CCSS.3.OA.B.5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression rewritten using the distributive law?

4 times 8 plus 3

4 times 8 plus 4 times 3

8 times 4 plus 3

8 times 4 plus 8 times 3

Tags

CCSS.3.OA.C.7

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 4 times 8?

32

40

36

28

Tags

CCSS.3.OA.C.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of 4 times 3?

10

13

11

12

Tags

CCSS.2.OA.C.4

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