Understanding Work in Thermodynamic Processes

Understanding Work in Thermodynamic Processes

Assessment

Interactive Video

Physics, Science

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains various thermodynamic processes using PV diagrams, including isobaric, isochoric, isothermal, adiabatic, and cyclic processes. It details how to calculate work done by gases in these processes, emphasizing the importance of understanding the area under the curve in PV diagrams. The tutorial provides formulas and examples for each process, highlighting key concepts like constant pressure, volume, and temperature, as well as the significance of direction in cyclic processes.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In an isobaric process, if a gas expands from 4 liters to 12 liters at a constant pressure of 5 atm, how much work is done by the gas in joules?

2026 joules

4052 joules

1013 joules

5065 joules

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the work done by a gas in an isochoric process when the pressure changes from 4 atm to 2 atm?

2026 joules

4052 joules

1013 joules

Zero

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In an isothermal process, what formula is used to calculate the work done by the gas?

CVΔT

nRT ln(Vf/Vi)

PΔV

PV = nRT

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For an isothermal expansion of 5 moles of nitrogen gas from 3 liters to 9 liters at 400 K, what is the work done by the gas?

18269 joules

4052 joules

5065 joules

1013 joules

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In an adiabatic process, what is the value of heat transferred?

Positive

Negative

Zero

Depends on the process

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the work done by argon gas expanding adiabatically from 0.01 m³ at 20x10⁵ Pa to 0.03 m³ at 4x10⁵ Pa?

48000 joules

36000 joules

12000 joules

24000 joules

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a cyclic process, how is the work done determined?

By the change in temperature

By the change in pressure

By the area under the PV curve

By the change in volume

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