
Solving Linear Systems by Substitution

Interactive Video
•
Mathematics
•
8th - 10th Grade
•
Medium
+2
Standards-aligned

Sophia Harris
Used 17+ times
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving a linear system using the substitution method?
Add the equations together
Multiply both equations by a constant
Isolate one of the variables
Graph the equations
Tags
CCSS.6.EE.B.7
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it beneficial to choose the variable with the lowest coefficient when isolating a variable?
It simplifies the graphing process
It makes the calculations faster
It helps avoid fractions
It ensures the solution is unique
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
After isolating a variable in the first equation, what should be done next?
Check the solution with a calculator
Substitute it back into the same equation
Substitute it into the second equation
Solve for the other variable directly
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the second example, why is the second equation chosen for substitution?
It has fewer terms
It results in a simpler graph
The numbers are multiples of each other
It has smaller coefficients
Tags
CCSS.7.EE.B.4A
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the advantage of solving for the variable with the lowest coefficient?
It reduces the number of steps
It avoids the use of fractions
It makes the solution more accurate
It simplifies the graphing process
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the third example, why is the first equation preferred despite the presence of fractions?
It has more terms
It results in fewer fractions
It has a higher coefficient
It is easier to graph
Tags
CCSS.8.EE.C.7B
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can fractions be eliminated when solving equations?
By subtracting the numerator from both sides
By multiplying every term by the denominator
By adding a constant to both sides
By dividing every term by the numerator
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
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