Using the law of sines when there are two cases

The video tutorial explains how to solve triangle problems using the law of sines. It begins by identifying the importance of ratios in triangles and checking for two cases when dealing with acute angles. The instructor demonstrates how to calculate the sine of angle A and find the second possible angle using reflection. Two triangles are drawn to represent different angle cases, and the process of solving for angle C in both scenarios is detailed.

What is the first step when provided with a triangle and a ratio?

• Calculate the area of the triangle

• Apply the law of sines

• Check for an acute angle

• Use the law of cosines

When dealing with a triangle with one acute angle, what must you check for?

• The length of the hypotenuse

• Two possible cases

• The area of the triangle

• The type of triangle

How do you find the other angle with the same sine value?

• Subtract from 180 degrees

• Subtract from 360 degrees

• Add 90 degrees

• Add 180 degrees

What is the angle C when angle A is 40.92 degrees?

• 15.92 degrees

• 114.08 degrees

• 139.08 degrees

• 25 degrees

What is the angle C when angle A is 139 degrees?

• 114.08 degrees

• 15.92 degrees

• 25 degrees

• 40.92 degrees

What is the sine ratio used to find the length of C in the first triangle?

• Sine of 40.92 / 6.2

• Sine of 25 / 4

• Sine of 114.08 / C

• Sine of 15.92 / C

What is the sine ratio used to find the length of C in the second triangle?

• Sine of 114.08 / C

• Sine of 40.92 / 6.2

• Sine of 25 / 4

• Sine of 15.92 / C