Pre-Calculus - Using Double Angle Formulas to Help Solve for Solutions to an Equation

Pre-Calculus - Using Double Angle Formulas to Help Solve for Solutions to an Equation

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Quizizz Content

FREE Resource

The video tutorial covers solving trigonometric equations involving cosine. It begins with an introduction to the problem and reviews methods such as reverse operations and factoring. The instructor then applies multiple angle formulas to simplify the equation, using identities to express everything in terms of cosine. Finally, the equation is factored, and solutions are found using the unit circle, focusing on solutions within one revolution.

Read more

7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation cosine of 2X minus cosine of X equals 0?

Use reverse order of operations

Combine like terms

Graph the equation

Apply the quadratic formula

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is chosen to express cosine of 2X in terms of cosine and sine?

Cosine squared plus sine squared

Sine squared minus cosine squared

Cosine plus sine

Cosine squared minus sine squared

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What identity is used to replace sine squared of X in the equation?

Sine equals cosine

Cosine squared equals 1 minus sine squared

Tangent equals sine over cosine

Sine squared equals 1 minus cosine squared

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After substitution, what type of problem does the equation become?

A graphing problem

A linear equation

A factoring problem

A differential equation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of cosine of X when X equals 0 on the unit circle?

0

1

1/2

-1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

At which angles is cosine of X equal to -1/2 on the unit circle?

0 and π

π/3 and 2π/3

2π/3 and 4π/3

π/2 and 3π/2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are only solutions between 0 and 2π considered?

To find all possible solutions

To focus on one revolution of the unit circle

To avoid complex numbers

To simplify the problem