Graphing a system of three linear inequalities using slope intercept form ex 18

The video tutorial demonstrates how to graph a system of three linear inequalities. It begins with converting the inequalities into slope-intercept form, followed by graphing each inequality on a coordinate plane. The tutorial emphasizes identifying the y-intercept and slope for accurate graphing. It also covers testing solutions using a test point to determine the correct shading for the feasible region. The tutorial concludes with identifying the feasible region formed by the inequalities.

What is the first step in graphing a system of linear inequalities?

• Plot random points

• Find the x-intercepts

• Convert them to slope-intercept form

• Convert them to standard form

How do you solve for y in the inequality 3x + 4y ≤ 15?

• Multiply both sides by 4

• Add 3x to both sides

• Divide both sides by 3

• Subtract 3x from both sides

What is the slope of the line represented by the inequality 2y + 5x > -12?

• -5/2

• 5/2

• -2/5

• 2/5

When graphing the inequality y ≤ 3/4x + 15/4, what type of line should be used?

• Dashed line

• Solid line

• Dotted line

• No line

What is the y-intercept of the inequality y > 27/10x - 8/5?

• 2.7

• 1.6

• 0.6

• 3.5

Which test point is commonly used to determine the shading of a region?

• (2,2)

• (1,1)

• (0,0)

• (-1,-1)

What shape is the feasible region formed by the system of inequalities?

• Rectangle

• Circle

• Square

• Triangle