Projectile motion Example problem 1

The video tutorial explains a projectile motion problem involving a cannonball fired from a mountain. It covers setting up the problem with axes, splitting velocity into components, and using integration to find velocity and displacement equations. The tutorial concludes by solving for the horizontal distance traveled by the projectile, emphasizing the importance of initial conditions and boundary values.

What is the initial speed of the cannonball?

• 20 meters per second

• 15 meters per second

• 10 meters per second

• 5 meters per second

At what angle is the cannonball fired from the horizontal?

• 15 degrees

• 45 degrees

• 30 degrees

• 60 degrees

Which formula represents the relationship between velocity and acceleration?

• V^2 = U^2 + 2AS

• DV = A * DT

• S = UT + 0.5AT^2

• DX = V * DT

What is the horizontal component of the initial velocity?

• 10 sin(30)

• 10

• 10 cos(30)

• 10 tan(30)

What is the acceleration in the vertical direction?

• 9.81 m/s^2

• 0 m/s^2

• 19.62 m/s^2

• -9.81 m/s^2

What is the initial vertical velocity of the cannonball?

• 10 sin(30)

• 0

• 10 cos(30)

• 9.81

What is the purpose of setting the initial conditions in this problem?

• To find the time of flight

• To determine the range

• To solve for integration constants

• To calculate the maximum height

What is the value of the horizontal distance traveled by the projectile?

• 75 meters

• 43.68 meters

• 52.51 meters

• 60 meters

Why is one of the solutions to the quadratic equation negative?

• It represents a backward motion

• It is an error in calculation

• It is a placeholder value

• It is due to the symmetry of the parabola

What is the significance of the positive solution in the context of this problem?

• It shows the initial velocity

• It gives the horizontal distance traveled

• It represents the total time of flight

• It indicates the maximum height