Kinetics of Branched Reaction Schemes Using Steady-State Approximation

Kinetics of Branched Reaction Schemes Using Steady-State Approximation

Assessment

Interactive Video

Science, Chemistry

University

Hard

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This video tutorial explains how to derive a rate law using steady state approximation kinetics. It covers the equilibrium of reactants A and B with intermediate C, which can branch into products D and E. The tutorial details the derivation of the rate law for intermediate C, using rate constants K1, K-1, K2, and K3. It then calculates the rates of formation for products D and E, highlighting the differences in rate constants. The video concludes with a summary of handling branched reaction sequences using steady state approximation.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the role of molecule C in the reaction setup described in the video?

It is a reactant.

It is a catalyst.

It is an intermediate.

It is a final product.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which assumption is crucial for applying the steady state approximation in kinetics?

The rate of change of the intermediate is zero.

The concentration of reactants is constant.

The temperature remains constant.

The reaction is at equilibrium.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the concentration of intermediate C expressed in terms of rate constants and reactants?

K1 * A * B / (K2 + K3)

K1 * A * B / (K-1 + K2 + K3)

K2 * A * B / (K1 + K3)

K3 * A * B / (K1 + K2)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What determines the difference in the rate of formation of D and E?

The concentration of A and B.

The temperature of the reaction.

The rate constants K2 and K3.

The equilibrium constant K1.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of the video, what does the rate constant K2 represent?

The rate of formation of E.

The equilibrium constant.

The rate of formation of D.

The reverse reaction rate.