How to solve a trigonometric equation with sine and cosine

How to solve a trigonometric equation with sine and cosine

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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Quizizz Content

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The video tutorial revisits solving linear and quadratic equations, emphasizing the use of inverse operations and factoring. It then transitions to solving trigonometric equations, highlighting the challenges of dealing with sine and cosine functions. The instructor explains the use of Pythagorean identities and factoring techniques, including handling negatives. The session concludes with finding solutions to trigonometric equations, using the unit circle and understanding the domain of inverse functions.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary method used to solve quadratic equations as discussed in the video?

Factoring and setting the equation to zero

Using the quadratic formula

Graphing the equation

Completing the square

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't we directly solve for sine or cosine in trigonometric equations?

Because they are undefined

Because they are not real numbers

Because they are always positive

Because they involve other trigonometric functions in the answer

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What identity is suggested to use when encountering a squared trigonometric function?

Reciprocal identities

Pythagorean identities

Even-odd identities

Quotient identities

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the teacher's preferred method when dealing with negative factors in equations?

Factor out the negative

Use a calculator

Ignore the negative

Multiply by a positive number

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the domain of the inverse sine function?

Between -2 and 2

Between -1 and 1

Between 0 and π

Between -π and π

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the solutions for sine of X equals 1/2 on the unit circle?

π/2 and 3π/2

π/6 and 5π/6

π/4 and 3π/4

π/3 and 2π/3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you find all solutions for a trigonometric equation within a given interval?

By subtracting 2π from each solution

By subtracting π from each solution

By adding π to each solution

By adding 2π to each solution