How to use the product rule then chain rule with secant

How to use the product rule then chain rule with secant

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains how to apply the product rule and chain rule in calculus to find derivatives of complex functions. It begins with an introduction to the product rule, followed by a step-by-step application to specific functions. The tutorial highlights challenges in deriving the secant function and demonstrates the use of the chain rule to address these challenges. Finally, it combines the results to form the final derivative expression.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the product rule used for in calculus?

To integrate a product of two functions

To differentiate a product of two functions

To find the limit of a function

To differentiate a sum of functions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of the function F(x) = 5x^2?

10x

5x

15x

20x

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the chain rule necessary for differentiating secant(3x)?

Because secant(3x) is a polynomial

Because 3x is a constant

Because secant(3x) is a composite function

Because secant is a trigonometric function

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of G(x) = secant(x) using the chain rule?

Tangent(x) * Sine(x)

Secant(x) * Cosine(x)

Cosine(x) * Tangent(x)

Secant(x) * Tangent(x)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final expression for the derivative of the product of F(x) = 5x^2 and G(x) = secant(3x)?

15x secant(3x) + 10x^2 secant(3x) tangent(3x)

10x secant(3x) + 5x^2 secant(3x) tangent(3x)

5x secant(3x) + 10x^2 secant(3x) tangent(3x)

10x secant(3x) + 15x^2 secant(3x) tangent(3x)