Crystal Lattice Structures: Density Calculation 1

Crystal Lattice Structures: Density Calculation 1

Assessment

Interactive Video

Physics

11th - 12th Grade

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to calculate the density of Gadolinium, which forms a hexagonal close packed structure. The atomic radius is given, and a conversion factor is used to express it in centimeters. The density formula for hexagonal close packed structures is applied, involving the atomic mass and Avogadro's number. The tutorial emphasizes the importance of using correct parentheses in calculations. The final density is calculated and rounded to 7.92 grams per cubic centimeter.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of structure does Gadolinium form?

Cubic close packed

Face-centered cubic

Hexagonal close packed

Body-centered cubic

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the conversion factor from angstroms to centimeters?

1 angstrom = 10^-8 cm

1 angstrom = 10^-7 cm

1 angstrom = 10^-10 cm

1 angstrom = 10^-9 cm

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the density of a hexagonal close packed structure?

Density = mass/volume

Density = 6 * atomic mass / (24√2 * radius^3)

Density = atomic mass / volume

Density = 4 * atomic mass / (π * radius^3)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molecular weight of Gadolinium used in the calculation?

155.25 grams per mole

160.25 grams per mole

150.25 grams per mole

157.25 grams per mole

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated density of Gadolinium in grams per cubic centimeter?

7.72

7.92

7.82

8.02

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