How to solve a quadratic when there are no solutions

The video tutorial explains how to set up and attempt to solve the quadratic equation y = X^2 + 5. It discusses the process of setting y to zero and solving for X, highlighting the issue of taking square roots of negative numbers. The tutorial concludes that there are no X intercepts or solutions for negative numbers and hints at future lessons on handling negatives.

What is the first step in solving the equation y = X^2 + 5 for X intercepts?

• Add 5 to both sides

• Set Y to 0

• Multiply both sides by 2

• Divide both sides by X

Why can't we find X intercepts for the equation X^2 + 5 = 0?

• Because the equation is not quadratic

• Because there are no real numbers that multiply to give a negative result

• Because X^2 is always positive

• Because 5 is too large

What is the result of multiplying -2 by -2?

• 2

• 0

• 4

• -4

What should you write if there are no X intercepts for a negative number?

• X intercepts are positive

• X intercepts exist

• No solutions

• Solutions exist

What will be covered later in the year regarding negative numbers?

• How to add them

• How to multiply them

• How to deal with them in equations

• How to divide them