Solving trigonometric equations with multiple angles

Solving trigonometric equations with multiple angles

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains how to solve sine equations, specifically when sine of 2X equals -sqrt(3)/2. It begins by identifying angles on the unit circle where sine equals -sqrt(3)/2, then addresses solving for 2X instead of X. The tutorial continues by finding all solutions using coterminal angles and concludes with the final solution for X.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial step in solving the equation sin(2X) = -√3/2?

Find solutions in the interval [0, 4π]

Find solutions in the interval [π, 2π]

Find solutions in the interval [0, 2π]

Find solutions in the interval [0, π]

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which angles on the unit circle have a sine value of -√3/2?

π/6 and 5π/6

π/4 and 3π/4

π/3 and 2π/3

4π/3 and 5π/3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of coterminal angles in solving trigonometric equations?

They are irrelevant to the solution

They help find solutions within a single interval

They allow for finding multiple solutions by adding or subtracting 2π

They are used to simplify the equation

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find all possible solutions for X in the equation sin(2X) = -√3/2?

By adding π to each solution

By subtracting π from each solution

By dividing the angles by 2 and considering coterminal angles

By multiplying the angles by 2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the final solutions for X in terms of π and a variable N?

X = π/4 + πN and X = 5π/6 + πN

X = π/2 + πN and X = 3π/4 + πN

X = 5π/6 + πN and X = 2π/3 + πN

X = π/3 + πN and X = 2π/3 + πN