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Pre-Calculus - Simplifying an imaginary number when a denominator -7 / i , -7/root(3)

Pre-Calculus - Simplifying an imaginary number when a denominator -7 / i , -7/root(3)

Assessment

Interactive Video

Mathematics, Information Technology (IT), Architecture

11th Grade - University

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to rationalize denominators in fractions, focusing on cases involving square roots and imaginary numbers. It provides examples of multiplying by conjugates to eliminate square roots from the denominator and discusses the process of handling imaginary numbers in the denominator by multiplying by the complex conjugate.

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of multiplying by the square root over itself when rationalizing a denominator?

To simplify the numerator

To make the fraction more complex

To eliminate the square root from the denominator

To change the value of the fraction

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example given, why is it important to multiply by 2/2 instead of just 2?

To change the fraction to a different value

To ensure the fraction remains equivalent

To make the fraction larger

To simplify the numerator

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying 'i' by itself?

1

-1

i

0

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When simplifying a fraction with 'i' in the denominator, what must you do?

Multiply only the denominator by 'i'

Multiply only the numerator by 'i'

Add 'i' to the numerator

Multiply both the numerator and denominator by 'i'

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equivalent expression of -7i over i squared?

7

-7

7i

-7i

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