Solve an equation with a rational term

Solve an equation with a rational term

Assessment

Interactive Video

Mathematics, Information Technology (IT), Architecture

11th Grade - University

Hard

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The video tutorial explains how to solve a complex rational equation by finding the least common denominator and using synthetic division. It guides through solving the equation step-by-step, ensuring the solution is verified and checking for any extraneous solutions.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What makes the initial problem appear complicated?

The lack of a clear solution.

The use of complex numbers.

The presence of multiple variables and rational terms.

The absence of any denominators.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of finding the least common denominator in this problem?

To solve the equation using a different method.

To change the variables in the equation.

To simplify the equation by eliminating denominators.

To add more complexity to the equation.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What method is used to prove that K + 2 divides into K^2 + 7K + 10?

Factoring

Long division

Graphing

Synthetic division

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying every term by the least common denominator?

The equation remains unchanged.

The equation becomes quadratic.

The equation becomes more complex.

The equation becomes linear.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the solution to the equation after simplification?

K = 2

K = 0

K = -1

K = 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to check for extraneous solutions?

Because it confirms the equation is quadratic.

Because multiplying by variables can introduce false solutions.

Because it simplifies the equation further.

Because it changes the variables.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final step in verifying the solution?

Ignoring the solution.

Changing the variables.

Rewriting the equation in a different form.

Plugging the solution back into the original equation.