What is the condition for a point to be a maximum based on the first derivative?
Stationary Points and Points of Inflection: Finding and Analyzing

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Mathematics
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University
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Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The gradient is zero.
The gradient changes from negative to positive.
The gradient changes from positive to negative.
The gradient remains constant.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the context of the curve y = x^3, what does a second derivative of zero indicate?
A point of inflection
No information
A maximum point
A minimum point
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For the curve y = x^5 - 4x^4 + 4x^3, what are the x-values of the stationary points?
1, 2, 3
0, 2, 1.2
0, 1, 2
0, 1.5, 2.5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the nature of the stationary point at x = 2 for the curve y = x^5 - 4x^4 + 4x^3?
Saddle point
Minimum
Point of inflection
Maximum
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the nature of a stationary point using the second derivative?
If the second derivative is zero, it could be an inflection point.
If the second derivative is zero, it's always a maximum.
If the second derivative is negative, it's a minimum.
If the second derivative is positive, it's a maximum.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does a change in the gradient from plus to zero to plus indicate?
A point of inflection
A constant function
A minimum point
A maximum point
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final step in sketching the graph after finding the stationary points?
Factorize the equation
Determine the y-intercept
Calculate the third derivative
Join the points to form the curve
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