Stationary Points and Points of Inflection: Finding and Analyzing

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Mathematics
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University
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Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the condition for a point to be a maximum based on the first derivative?
The gradient is zero.
The gradient changes from negative to positive.
The gradient changes from positive to negative.
The gradient remains constant.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the context of the curve y = x^3, what does a second derivative of zero indicate?
A point of inflection
No information
A maximum point
A minimum point
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For the curve y = x^5 - 4x^4 + 4x^3, what are the x-values of the stationary points?
1, 2, 3
0, 2, 1.2
0, 1, 2
0, 1.5, 2.5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the nature of the stationary point at x = 2 for the curve y = x^5 - 4x^4 + 4x^3?
Saddle point
Minimum
Point of inflection
Maximum
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the nature of a stationary point using the second derivative?
If the second derivative is zero, it could be an inflection point.
If the second derivative is zero, it's always a maximum.
If the second derivative is negative, it's a minimum.
If the second derivative is positive, it's a maximum.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does a change in the gradient from plus to zero to plus indicate?
A point of inflection
A constant function
A minimum point
A maximum point
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final step in sketching the graph after finding the stationary points?
Factorize the equation
Determine the y-intercept
Calculate the third derivative
Join the points to form the curve
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