Solving Simultaneous Equations with a Quadratic: The Substitution Method and the Discriminant

Solving Simultaneous Equations with a Quadratic: The Substitution Method and the Discriminant

Assessment

Interactive Video

Mathematics

University

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains simultaneous equations, focusing on solving them using graphical and substitution methods. It introduces the concept of simultaneous equations, demonstrates solving them graphically by finding intersection points, and explains the substitution method for algebraic solutions. The discriminant is also discussed as a tool to determine the number of solutions. Example problems are solved to illustrate these methods, and the tutorial concludes with a summary of key points.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a simultaneous equation?

An equation with one unknown variable

An equation involving two or more unknowns with the same values

An equation that can only be solved graphically

An equation that has no solutions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example given, what are the two equations used to illustrate simultaneous equations?

y = x + 6 and y = x^2 - 2x + 2

y = x - 6 and y = x^2 + 2x - 2

y = x^2 + 6 and y = x - 2x + 2

y = x + 2 and y = x^2 - 6x + 2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the point of intersection represent in the graphical solution of simultaneous equations?

The solution to the simultaneous equations

The point where the graph crosses the x-axis

The midpoint of the graph

The point where the graph crosses the y-axis

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main method used to solve simultaneous equations involving a quadratic?

Trial and error

Elimination method

Substitution method

Graphical method

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a positive discriminant indicate about the solutions of a quadratic equation?

No solutions

Infinite solutions

Two solutions

One solution

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you rearrange the equation 2y - x = 0 to solve for y?

y = 2x

y = x - 2

y = x / 2

y = x + 2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying the equation x^2 + x^2/4 = 20 by 4?

x^2 = 20

4x^2 + x^2 = 80

x^2 = 16

5x^2 = 80

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