Trigonometry | Preparing for Precalculus Part 6

Trigonometry | Preparing for Precalculus Part 6

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

Created by

Quizizz Content

FREE Resource

This video is the final part of a series preparing students for precalculus, focusing on trigonometry. It covers the Pythagorean theorem, trigonometric functions, and special right triangles. The instructor reviews solving triangle problems using these concepts, emphasizing understanding relationships and simplifying radicals. The video aims to equip students with the necessary skills for success in precalculus.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of this video tutorial?

Calculus concepts

Trigonometry problems

Algebraic expressions

Geometry proofs

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a right triangle, what is the longest side called?

Base

Hypotenuse

Opposite

Adjacent

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which theorem is used to find the missing side of a right triangle?

Tangent Rule

Sine Rule

Pythagorean Theorem

Cosine Rule

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the sine of an angle in a right triangle?

Adjacent over Hypotenuse

Opposite over Hypotenuse

Opposite over Adjacent

Hypotenuse over Adjacent

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric function relates the opposite side to the adjacent side?

Sine

Cosine

Tangent

Secant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for a missing side using the tangent function?

Divide the adjacent side by the tangent of the angle

Multiply the opposite side by the tangent of the angle

Multiply the adjacent side by the tangent of the angle

Divide the opposite side by the tangent of the angle

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between the sides of a 45-45-90 triangle?

The legs are equal, and the hypotenuse is twice the leg

The legs are equal, and the hypotenuse is the leg times sqrt(2)

The hypotenuse is twice the length of one leg

The hypotenuse is the leg times sqrt(3)

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