Using two 30 60 90 triangles to determine the missing lengths of a figure

Using two 30 60 90 triangles to determine the missing lengths of a figure

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains the properties of 30-60-90 triangles, focusing on solving for missing values X and Y. It discusses the importance of separating triangles into smaller parts to simplify calculations. The tutorial covers how to calculate the short and long legs of a triangle using the hypotenuse and rationalizing denominators to find final answers.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving for missing values in a triangle divided into two 30-60-90 triangles?

Use a calculator to find the angles

Combine the triangles into one large triangle

Ignore the 90-degree angle

Separate the triangles into two smaller triangles

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a 30-60-90 triangle, how do you find the short leg if you know the hypotenuse?

Divide the hypotenuse by sqrt 2

Multiply the hypotenuse by sqrt 3

Divide the hypotenuse by 2

Multiply the hypotenuse by 2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between the short leg and the long leg in a 30-60-90 triangle?

The long leg is the short leg divided by sqrt 3

The long leg is the short leg times sqrt 3

The long leg is the short leg plus 2

The long leg is twice the short leg

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you rationalize the denominator when calculating side lengths in a 30-60-90 triangle?

Subtract the denominator from the numerator

Add the denominator to the numerator

Multiply by the reciprocal of the denominator

Multiply by the square root of the denominator

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the final values of X and Y in the special triangle discussed?

X = 7, Y = 7

X = 7 sqrt 3, Y = 7 sqrt 2

X = 7 sqrt 2, Y = 7 sqrt 3

X = 7 sqrt 3 / 2, Y = 7 sqrt 2 / 3