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Finding the vertices, foci and asymptotes of a hyperbola

Finding the vertices, foci and asymptotes of a hyperbola

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explains how to analyze a hyperbola equation by finding its center, vertices, foci, and asymptotes. It begins with identifying the center using the H and K values, then moves on to determine the vertices by understanding the transverse axis. The tutorial also covers calculating the foci using the formula C^2 = a^2 + b^2 and approximating their positions without a calculator. Finally, it explains how to derive the equations for the asymptotes, emphasizing the importance of understanding the relationship between the variables and the hyperbola's orientation.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the center of the hyperbola given by the equation X - 1^2 / 4 - Y + 2^2 / 1 = 1?

(1, 2)

(-1, -2)

(-1, 2)

(1, -2)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine if a hyperbola has a horizontal or vertical transverse axis?

By the coefficient of X

By the sign of the equation

By the value of B^2

By which variable is above A^2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the coordinates of the vertices for the hyperbola with center (1, -2) and a^2 = 4?

(3, 2) and (-1, 2)

(0, -2) and (2, -2)

(1, 0) and (1, -4)

(3, -2) and (-1, -2)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the distance to the foci of a hyperbola?

C^2 = a^2 - b^2

C = a - b

C^2 = a^2 + b^2

C = a + b

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate value of sqrt(5) used to find the foci?

2.2

2.5

2.8

2.0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation for the asymptotes of a hyperbola with a horizontal transverse axis?

y = h ± (a/b)(x - k)

y = h ± (b/a)(x - k)

y = k ± (a/b)(x - h)

y = k ± (b/a)(x - h)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the equations of the asymptotes derived in the video?

y = 1/2x + 3/2 and y = -1/2x + 5/2

y = 1/2x - 3/2 and y = -1/2x - 5/2

y = 1/2x + 5/2 and y = -1/2x + 3/2

y = 1/2x - 5/2 and y = -1/2x - 3/2

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