Physics Kinematics: Motion in a Straight Line - Equations of Motion Part 1

Physics Kinematics: Motion in a Straight Line - Equations of Motion Part 1

Assessment

Interactive Video

Arts, Other, Physics, Science

4th Grade - University

Hard

Created by

Quizizz Content

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This video tutorial covers the equations of motion for uniform acceleration, known as SUVAT equations. It explains the variables involved and emphasizes the importance of sign conventions. The tutorial includes examples, such as a sphere accelerated by a tractor beam and a tennis ball thrown upwards, to demonstrate the application of these equations. It also highlights the process of solving physics problems, including underlining key information, drawing diagrams, and selecting appropriate equations. The video concludes with a review of key concepts and tips for avoiding common mistakes in physics calculations.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary condition for using the equations of motion discussed in this lesson?

The object must be moving in a circular path.

The acceleration must be constant.

The object must be at rest initially.

The velocity must be increasing.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of the equations of motion, what does the symbol 'S' represent?

Speed

Displacement

Acceleration

Time

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When solving for the acceleration of the sphere, which equation of motion is used?

s = ut + 1/2 at^2

v^2 = u^2 + 2as

s = vt - 1/2 at^2

v = u + at

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final velocity of the sphere after 2.9 seconds of acceleration?

0.11 m/s

0.32 m/s

1.1 m/s

3.2 m/s

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the tennis ball example, why is the displacement considered negative?

The ball is moving west.

The ball is moving upwards.

The ball is moving east.

The ball finishes below its starting position.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation is used to find the velocity of the tennis ball when it hits the ground?

s = vt - 1/2 at^2

v^2 = u^2 + 2as

s = ut + 1/2 at^2

v = u + at

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial velocity of the diamond fragment when it is launched?

11.3 m/s

4.9 m/s

0 m/s

9.8 m/s

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