How to solve a word problem involving the cube root

How to solve a word problem involving the cube root

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial covers solving a geometry problem involving the volume of a sphere. It begins by introducing the formula for volume and emphasizes the importance of identifying and defining variables. The tutorial then demonstrates solving for the radius when given a specific volume and addresses a scenario where the volume is increased by a factor of eight, requiring recalculation of the radius.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step you should take when approaching a word problem involving equations?

Solve the equation immediately.

Ignore the given equation.

Identify and define the variables.

Guess the answer.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the variable 'v' represent in the formula for the volume of a sphere?

Diameter

Circumference

Radius

Volume

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When given the volume of a sphere as 36π, what is the first step to find the radius?

Subtract 36

Divide by 4/3

Add 4/3

Multiply by π

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for the radius when the equation is 36 = 4/3 r³?

Subtract 4/3

Divide by 4/3

Multiply by 4/3

Multiply by 3/4

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the volume of a sphere is increased by a factor of 8, what happens to the radius?

It remains the same.

It doubles.

It triples.

It halves.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the new volume if the original volume of 36π is increased by a factor of 8?

324π

288π

144π

72π

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the new radius when the volume is increased to 288π?

3

6

9

12